25届秋招科大讯飞飞凡计划研发-第八批
25届秋招科大讯飞飞凡计划研发-第八批
时间:2024-08-30 19:00
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编程
1


cpp
// Description: 25届秋招科大讯飞飞凡计划研发-第八批
// Accept: 100%
// Date: 2024/08/30
#include <cmath>
#include <iostream>
using namespace std;
int main() {
int T, h, r, x0, v1, v2;
while (cin >> T) { // 注意 while 处理多个 case
while (T-- > 0) {
cin >> h >> r >> x0 >> v1 >> v2;
// 箭走的路程
double arrow_len = sqrt(h * h + x0 * x0);
double arrow_time = arrow_len / v2;
// 爆炸时小紫的位置
double position = v1 * arrow_time;
if (position >= x0 - r && position <= x0 + r) {
cout << "Yes" << endl;
} else {
cout << "No" << endl;
}
}
}
return 0;
}
// 64 位输出请用 printf("%lld")
2


cpp
// Description: 25届秋招科大讯飞飞凡计划研发-第八批
// Accept: 62.5% Timeout
// Date: 2024/08/30
#include <algorithm>
#include <iostream>
#include <unordered_set>
#include <vector>
using namespace std;
int main() {
int n, q, l, r;
while (cin >> n >> q) { // 注意 while 处理多个 case
std::vector<int> arr(n);
std::vector<std::unordered_set<int>> position(n);
for (int i = 0; i < n; ++i) {
position[i] = std::unordered_set<int>();
}
for (int i = 0; i < n; ++i) {
arr[i] = i + 1;
}
while (q-- > 0) {
cin >> l >> r;
// moveToEnd
std::rotate(arr.begin() + l - 1, arr.begin() + r, arr.end());
// 只需统计移动后的,[l-1:arr.size()]的
for (int i = l - 1; i < arr.size(); ++i) {
if (arr[i] == i + 1) {
continue;
}
position[arr[i] - 1].insert(i);
}
}
for (int i = 0; i < n; ++i) {
cout << position[i].size() + 1 << " ";
}
cout << endl;
}
return 0;
}
// 64 位输出请用 printf("%lld")
3



cpp
// Description: 25届秋招科大讯飞飞凡计划研发-第八批
// Accept: 86.6% Wrong Answer
// Date: 2024/08/30
#include <iostream>
#include <vector>
using namespace std;
int getResult(vector<int>& nums) {
int res = 0;
for (int i = 0, ones = 0; i < nums.size(); ++i) {
if (nums[i] == 1) {
++ones;
} else {
res += ones * ones;
ones = 0;
continue;
}
if (i == nums.size() - 1) {
res += ones * ones;
}
}
return res;
}
void longestOnes(vector<int>& nums, int k, int& ansl, int& ansr) {
int n = nums.size();
int left = 0, lsum = 0, rsum = 0;
int ans = 0;
for (int right = 0; right < n; ++right) {
rsum += 1 - nums[right];
while (lsum < rsum - k) {
lsum += 1 - nums[left];
++left;
}
if (right - left + 1 > ans) {
ans = right - left + 1;
ansl = left;
ansr = right;
}
}
}
int main() {
int n, k, ansl, ansr;
while (cin >> n >> k) { // 注意 while 处理多个 case
std::string s;
cin >> s;
vector<int> nums(s.size());
for (int i = 0; i < s.size(); ++i) {
nums[i] = s[i] == '0' ? 0 : 1;
}
if (k == 0) {
cout << getResult(nums) << endl;
break;
}
longestOnes(nums, k, ansl, ansr);
for (int i = ansl; i <= ansr; ++i) {
nums[i] = 1;
}
cout << getResult(nums) << endl;
}
}
// 64 位输出请用 printf("%lld")